(2xtany)dx+(sec^2y)dy=0

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Solution for (2xtany)dx+(sec^2y)dy=0 equation:


Simplifying
(2xtany) * dx + (sec2y) * dy = 0

Remove parenthesis around (2antxy)
2antxy * dx + (sec2y) * dy = 0

Multiply antxy * dx
2adntx2y + (sec2y) * dy = 0

Multiply c2esy * dy
2adntx2y + c2desy2 = 0

Solving
2adntx2y + c2desy2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1c2desy2' to each side of the equation.
2adntx2y + c2desy2 + -1c2desy2 = 0 + -1c2desy2

Combine like terms: c2desy2 + -1c2desy2 = 0
2adntx2y + 0 = 0 + -1c2desy2
2adntx2y = 0 + -1c2desy2
Remove the zero:
2adntx2y = -1c2desy2

Divide each side by '2dntx2y'.
a = -0.5c2en-1st-1x-2y

Simplifying
a = -0.5c2en-1st-1x-2y

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